Drizzle | 选择至少含有一个相关子行的父行
PostgreSQL
MySQL
SQLite
本指南演示了如何选择至少含有一个相关子行的父行。下面是 schema 定义和相应数据库数据的示例
import { integer, pgTable, serial, text } from 'drizzle-orm/pg-core';
export const users = pgTable('users', {
id: serial('id').primaryKey(),
name: text('name').notNull(),
email: text('email').notNull(),
});
export const posts = pgTable('posts', {
id: serial('id').primaryKey(),
title: text('title').notNull(),
content: text('content').notNull(),
userId: integer('user_id').notNull().references(() => users.id),
});
users.db
posts.db
+----+------------+----------------------+
| id | name | email |
+----+------------+----------------------+
| 1 | John Doe | [email protected] |
+----+------------+----------------------+
| 2 | Tom Brown | [email protected] |
+----+------------+----------------------+
| 3 | Nick Smith | [email protected] |
+----+------------+----------------------+
要选择至少含有一个相关子行并获取子数据的父行,可以使用 .innerJoin()
方法
import { eq } from 'drizzle-orm';
import { users, posts } from './schema';
const db = drizzle(...);
await db
.select({
user: users,
post: posts,
})
.from(users)
.innerJoin(posts, eq(users.id, posts.userId));
.orderBy(users.id);
select users.*, posts.* from users
inner join posts on users.id = posts.user_id
order by users.id;
// result data, there is no user with id 2 because he has no posts
[
{
user: { id: 1, name: 'John Doe', email: '[email protected]' },
post: {
id: 1,
title: 'Post 1',
content: 'This is the text of post 1',
userId: 1
}
},
{
user: { id: 1, name: 'John Doe', email: '[email protected]' },
post: {
id: 2,
title: 'Post 2',
content: 'This is the text of post 2',
userId: 1
}
},
{
user: { id: 3, name: 'Nick Smith', email: '[email protected]' },
post: {
id: 3,
title: 'Post 3',
content: 'This is the text of post 3',
userId: 3
}
}
]
若要仅选择至少含有一个相关子行的父行,可以使用带有 exists()
函数的子查询,如下所示
import { eq, exists, sql } from 'drizzle-orm';
const sq = db
.select({ id: sql`1` })
.from(posts)
.where(eq(posts.userId, users.id));
await db.select().from(users).where(exists(sq));
select * from users where exists (select 1 from posts where posts.user_id = users.id);
// result data, there is no user with id 2 because he has no posts
[
{ id: 1, name: 'John Doe', email: '[email protected]' },
{ id: 3, name: 'Nick Smith', email: '[email protected]' }
]